(x/3-2)^2=16

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Solution for (x/3-2)^2=16 equation: 


x in (-oo:+oo)

(x/3-2)^2 = 16 // - 16

(x/3-2)^2-16 = 0

(1/3*x-2)^2-16 = 0

(1/3*x-2)^2-16 = 0

1/9*x^2-4/3*x-12 = 0

1/9*x^2-4/3*x-12 = 0

1/9*x^2-4/3*x-12 = 0

DELTA = (-4/3)^2-(-12*1/9*4)

DELTA = 64/9

DELTA > 0

x = ((64/9)^(1/2)+4/3)/(1/9*2) or x = (4/3-(64/9)^(1/2))/(1/9*2)

x = 18 or x = -6

(x+6)*(x-18) = 0

(x+6)*(x-18) = 0

( x+6 )

x+6 = 0 // - 6

x = -6

( x-18 )

x-18 = 0 // + 18

x = 18

x in { -6, 18 }

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